Deriving the time-domain response of an equation, from a tf
    46 visualizzazioni (ultimi 30 giorni)
  
       Mostra commenti meno recenti
    
So I have the code to create a transfer function, from which you can get the graph of the step response:
G = tf([1], [1 0.9 5]);
step(G);
Easy. However I can't find a way to perform an inverse Laplace transform on G, to get an actual equation.
0 Commenti
Risposte (1)
  Benjamin Großmann
      
 il 24 Apr 2018
        
      Modificato: Benjamin Großmann
      
 il 24 Apr 2018
  
       G = tf([1], [1 0.9 5]);
 [num,den] = tfdata(G);
 syms s
 G_sym = poly2sym(cell2mat(num),s)/poly2sym(cell2mat(den),s)
You have to multiply the input in laplace domain to the transfer function to get the system response to a specific input in time domain:
 Y_lap_sym = G_sym/s; % U(s) = 1/s for the unit step
 y_time_sym = ilaplace(Y_lap_sym);
2 Commenti
  AAYUSH MARU
 il 3 Apr 2020
				clc;
clear all;
syms t;
t= 0:0.001:10
 G = tf([1], [1 0.9 5]);
 [num,den] = tfdata(G);
 syms s
 G_sym = poly2sym(cell2mat(num),s)/poly2sym(cell2mat(den),s)
  Y_four_sym = G_sym/s; % U(s) = 1/s for the unit step
 y_time_sym = ifourier(Y_four_sym);
 y_n = double(y_time_sym);
 subplot(2,1,1)
 plot(t,y_time_sym);
how to plot step response here?
Vedere anche
Categorie
				Scopri di più su Calculus in Help Center e File Exchange
			
	Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!



