create a variable number of nested for loops? select elements in matrix with variables dimensions?

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hi,
i have a fucntion with a matrix that has variables dimensions (depends on a parameter given in input) and i would like to scan all the elements inside, but the fact is that i don't know how to nest many for loops.
let´s make an example: M is a matrix 3 dimensional with length [2,4,6]
i would like to do:
for i1:1=2
for i2:1=4
for i3:1=6
M(i1,i2,i3) = 0;
end
end
end
as you can notice, i need 3 loops, but how to use N loops, with N the number of dimensions of M (N is fixed once that function is called)? i thought about using eval, but it seems not working..
another related question, i would like to access to element M(i1,i2,i3) if N=3 or M(i1,i2,i3,i4,i5) if N=5, should i use eval also in this case, or is there any better solution?
thanks in advance

Risposta accettata

Walter Roberson
Walter Roberson il 30 Mag 2012
The particular example you give can be written as
M(1:2,1:4,1:6) = 0;
With regards to the nested loop: turn them into a single loop using an "odometer" type mechanism. See my code in https://groups.google.com/group/comp.lang.c/browse_thread/thread/d98842738fa27a55/2f6d5ff877063de1 and Chris Torek's useful modification there.
With regard to variable number of subscripts:
subs = [i1, i2, i3, i4];
subscell = num2cell(subs);
M(subscell{:})
  3 Commenti
Walter Roberson
Walter Roberson il 30 Mag 2012
If all of the elements are to be set to 0 without disturbing the size or shape, then M(:) = 0 is easier.
Tom
Tom il 30 Mag 2012
Indeed, though in that case it would seem pointless generating the matrix in the first place (or just use the zeros function), so I assume there's some other stuff later in the loop.

Accedi per commentare.

Più risposte (2)

Andrea
Andrea il 8 Giu 2012
thanks, i didnt have the time to check your discussion..
of course there is much code inside the loops, i wrote m= 0 only to write something random inside

Henry Charlesworth
Henry Charlesworth il 30 Giu 2016
Modificato: Henry Charlesworth il 30 Giu 2016
So you can do it with eval although not sure it's particularly good practice:
%
nLoops=3;
str = '';
for i=1:nLoops
str = sprintf('%s \n for i%d=1:5',str,i);
end
str = sprintf('%s \n [i1 i2 i3]',str);
for i=1:nLoops
str = sprintf('%s \n end',str);
end
eval(str)

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