Azzera filtri
Azzera filtri

How to fix this loop to get the desired output ?

3 visualizzazioni (ultimi 30 giorni)
New_Td = [4,1,1]
for t = New_Td
for b = 1:t
duplicate(b) = 0;
r(b) = 0;
fprintf('Hai from %i\n',t);
disp(duplicate);
end
end
Output I am getting look like this: ->>>> WRONG OUTPUT WHICH I AM GETTING
if true
Hai from 4
0
Hai from 4
0 0
Hai from 4
0 0 0
Hai from 4
0 0 0 0
Hai from 1
0 0 0 0
Hai from 1
0 0 0 0
end
But CORRECT OUTPUT SHOULD BE LIKE THIS:
if true
Hai from 4
0
Hai from 4
0 0
Hai from 4
0 0 0
Hai from 4
0 0 0 0
Hai from 1
0
Hai from 1
0
end

Risposta accettata

Majid Farzaneh
Majid Farzaneh il 23 Mag 2018
Hi,
New_Td = [4,1,1]
for t = New_Td
duplicate=[];
for b = 1:t
duplicate(b) = 0;
r(b) = 0;
fprintf('Hai from %i\n',t);
disp(duplicate);
end
end
  1 Commento
Majid Farzaneh
Majid Farzaneh il 23 Mag 2018
At the first time for t=4, duplicate length become 4. When t become 1, duplicate length is still 4.
You should destroy duplicate and build it again after each iteration. The code above is work.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by