How to do this addition?

D = [60,600,15];

A(2) = D(2); -> OUTPUT OF A LOOKS LIKE A = [0,600]

B(3) = D(3); -> OUTPUT OF B LOOKS LIKE B = [0,0,15]

c = A + B;

disp(c);

How to make length of A as 3 and fill in zeros where the index is not used

Answer 1

[Image Analyst]

If you want A to be the same size as B, which may be less than the length of D depending on which indexes you're setting, then use Ameer's code, as long as B is also longer than A.

If you want A, B, and c all to be the same length as D, then do this:

% Initialize variables.
D = [60,600,15];
A = zeros(size(D)); % All zeros and the same size as D.
B = zeros(size(D));
% Now set whatever elements of A and B you want
% For example...
A(2) = D(2); % OUTPUT OF A LOOKS LIKE A = [0, 600, 0]
B(3) = D(3); % OUTPUT OF B LOOKS LIKE B = [0, 0, 15]
% Now add.
c = A + B;

Also, please see this link : http://www.mathworks.com/matlabcentral/answers/13205#answer_18099

Answer 2

[Ameer Hamza]

Make A same size as B

A = [A zeros(1, length(B)-length(A))]

and then add

C = A+B;