cart2pol angle sin 0 to 2pi range instead of -pi to pi range?
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Alexander Hannides Rajapakse on 28 May 2018
Answered: theodore panagos on 7 Nov 2018
I have a huge set of x and y coordinates that I have converted to polar coordinates using cart2pol, but I need to have my range of angles to be 0 to 2pi instead of -pi to pi. How can I do this without manually adding 2pi to each negative theta?
John D'Errico on 24 Oct 2018
The most efficient solution is to use mod. Thus...
theta = mod(cart2pol(x,y),2*pi);
This works, because what you really want is to add 2*pi to the angle, whenever the angle is less than zero. mod does exactly that. And, yes, mod works for non-integer moduli, and of course mod is vectorized, so it does everything you need without even a need for a loop.
theodore panagos on 7 Nov 2018
You can use the formula:
there is x=x2-x1 and y=y2-y1
The formula give the angle from 0 to2pi for all the values x and y
For x=y=0 the result is undefined.
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