How do I get the last element of a cell array from a function call?
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Elizabeth Cisneros
il 15 Lug 2018
Commentato: Image Analyst
il 16 Lug 2018
Say I am making a function call to a function that needs an index as one of its arguments, however, in this case, I only want the last element of the cell array. So far I have this:
twin_start = boundary_times(df,steplists,stepIdx,full_step_str,end);
using end as an argument, but I know you can't use end like that. Is there something I can do to indicate that I want the last element of the cell array when making a function call? Thank you :)
2 Commenti
Rik
il 15 Lug 2018
You mean you want only the last element of your output array? I have no idea what kind of input boundary_times is expecting, so I can't tell if you should use some call to numel or something totally different.
Risposta accettata
Stephen23
il 15 Lug 2018
Modificato: Stephen23
il 15 Lug 2018
Write the function to accept a special case, e.g. an empty array indicates end:
if isempty(location)
step_BoundaryT = twinSplit{end};
else
step_BoundaryT = twinSplit{location};
end
and then call it like this:
boundary_times(...,[]);
2 Commenti
Image Analyst
il 16 Lug 2018
Well changing the function was what I suggested to you in my earlier answer, but you said "I wouldn't want to hardcode it though because I use this function for other purposes". Glad to see you changed your mind. Obviously if nothing changes in your code (or input data), then nothing will change in the results.
Più risposte (1)
Image Analyst
il 15 Lug 2018
Try this:
% Put contents of last cell of the twinSplit cell array into step_BoundaryT
step_BoundaryT = twinSplit{end};
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