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How to convert a matrix to a structure array?

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I am working with data that is in a matrix but would like to easily convert it to a structure array. At the moment I am using the "table" and "table2struct" commands as per the simple example below but I feel that there should be a more efficient method that I'm missing as I will likely have far more than three variables and the current method I'm using seems inefficient. Any assistance would be appreciated!
T=table(M(:,1),M(:,2),M(:,3),'VariableNames',{'Var1' 'Var2' 'Var3'});
  2 Commenti
Steven Lord
Steven Lord il 18 Lug 2018
Why do you need to convert the matrix into a struct array? How are you planning to use the fields in the struct later in your code?
Personally most of the time I'd just leave it as M and use indexing to extract the columns as I need them.
Hannah il 19 Lug 2018
I normally work with the data as M as you suggest but I would like to transform the data to a struct array as it is more rigorous in terms ensuring that there is no confusion about which variable is which when making data publically accessible.

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Guillaume il 19 Lug 2018
I'm with Steven, it would make more sense to keep it as is, or if the columns indeed represent different things, to change it to a table. A simpler version of your conversion would be:
T = array2table(M, 'VariableNames', compose('Var%d', 1:size(M, 2)))
tables are a lot more flexible than structures as you can access data by row or by column. With a structure you're putting the emphasis on the columns at the expense of rows.
If you really want a structure, then, for a matrix with an arbitrary number of column:
S = cell2struct(num2cell(M, 1), compose('Var%d', 1:size(M, 2)), 2)

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