Azzera filtri
Azzera filtri

hi i want to calculate nth power for each value of s from 1 to 50 and store the result for each value of s in za varaible

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f=imread('lena1.jpg');
x=rgb2gray(f);
for s=1:50
za=x.^(s);
end
  1 Commento
Guillaume
Guillaume il 25 Lug 2018
Modificato: Guillaume il 25 Lug 2018
Oh! I see the question was edited. s starts as an image, then becomes an iterator. That's confusing! There are 26 letters in the alphabet, you don't have to limit yourself to just 2. Even better, use words for variable names as this makes the intent of the code clearer.
What is the desired output? What size should za be?

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Risposte (1)

Guillaume
Guillaume il 25 Lug 2018
Sounds like homework to me.
Do you have to use a loop? The normal matlab way is simply:
za = (1:50).^2;
If you do have to use a loop, index your za.
Note that there is a big difference between 2.^x and x.^2. The power operation is not commutative.
  3 Commenti
Guillaume
Guillaume il 25 Lug 2018
In your question, you wrote "calculate square" which .^2.
What does (image) mean? Perhaps, you should show a numerical example of input and corresponding desired output.
Guillaume
Guillaume il 25 Lug 2018
Modificato: Guillaume il 25 Lug 2018
Ok, so what do you want as output? Should za be a 3D array of size height(image) x width(image) x 50?
Perhaps, this is what you want:
img = im2double(rgb2gray(imread('lena1.jpg'));
s = 1:50;
za = img .^ permute(s, [1 3 2]); %MxNx50 array

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