How do I color points from scatter3 (3D scalar field), in accordance with their scalar values?
18 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Assume BB matrix is a 3D scalar field containing only {-1,1} The piece of code is (not working..) -
BB = reshape(last,[3*nthroot(cubes,3),3*nthroot(cubes,3),3*nthroot(cubes,3)]);
BB(~BB)=-1;
BBB = abs(fftn(BB)).^2;
[row,col,zz]=ind2sub(size(BBB),find(BBB));
map = [1 0 0
1 1 0];
figure
scatter3(col,row,zz,10,'filled','s');
colormap(map)
3 Commenti
Adam
il 7 Ago 2018
Modificato: Adam
il 7 Ago 2018
Your code was definitely less confusing first time round! Anything that is doing a scatter plot inside 3 nested for loops is almost certain to not be the best way (or a way at all) to do what you want.
If you just want to apply a colourmap to points you may be better off using plot3 with markers and no lines.
But personally I would just create my colourmap of however many points I want between red and yellow (I assume you mean RGB-space interpolation from red to yellow - i.e. green-scale interpolation).
Then there are numerous ways you could map your data onto it. Using
doc histcounts
would do it probably, using the same number of bins as you created elements in your colourmap. This will bin your data giving indices into the colourmap for each point. Then you can just combine these to give the colour argument in RGB for your scatter3 call.
Risposta accettata
Adam
il 7 Ago 2018
Modificato: Adam
il 7 Ago 2018
I don't have time to give full code, but the first option gives you what you need - i.e a single scatter3 instruction, not a massive nested loop. The 5th argument is an n*3 array of colours where n must be the same size as the number of points in your col, row, zz arrays.
Here is some example code you can hopefully adapt to your case:
e.g.
x = rand( 10,1);
y = rand( 10,1);
z = x.^2 + y.^2;
c = rand( 10, 3 ); % 10 random colours
figure; scatter3( x, y, z, [], c, 'filled' )
will give you a simple scatter plot with different coloured points.
Now all you need to do is, instead of creating 10 random colours as I did there, create a colourmap of the required size e.g.
cmap = [ ones( 256, 1 ), linspace( 0, 1, 256 )', zeros( 256, 1 ) ];
Now you have 256 colours between red and yellow. Your data needs to be binned to index into this colourmap though. This is doable by e.g.
a = rand( 1, 100000 ); % Lots of random continuous data
idx = discretize( a, 256 ); % discretise your data into 256 bins;
(In my original comment above I was going to suggest discretize, but missed that it had an option to supply number of bins rather than explicit edges so this is easier than histcounts which doesn't actually bin your data, it just gives the histogram counts as totals).
Then you have all your data in 256 bins and can use those indices into your colourmap.
c = cmap( idx, : );
should do this for you, and then you can use this as 'c' in my above scatter3 line instead of random colours.
2 Commenti
Adam
il 7 Ago 2018
Your row, coll and zz values come from the locations where BB is non-zero ( find( BBB ) ) whereas you appear to be discretizing the whole of BBB.
You probably need to pass
BBB(:)
to discretize though to end up with a column vector of indices to pass to the colourmap, rather than a 3d result which will likely not work.
Più risposte (1)
Vedere anche
Categorie
Scopri di più su Surface and Mesh Plots in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!