Azzera filtri
Azzera filtri

How can I do a drawing of this shape؟

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%File of Result of stress by FEM v=0.35;% Poission ratio sv=66;% vertical stress sh=45;% min horizontal stress Pp=30;% pore pressure sH=75; % max horizontal stress a=0.08;
m=0:39; r=a+(5..*10.^-3+0.1.*m); n=linspace(1,120,40) theta= (3./2+3.*(n-1)) az=0; inc=0; b=((a.^2)./(r.^2)); N=40; % eqn 3.2.6 sx = sH.*(cos(az).* cos(r)).^2 + sh.*(sin(az).*cos(inc)).^2 + sv.*(-sin(inc).^2); sy = sH.*(-sin(az)).^2 + sh.*(cos(az)^2); sz = sH.*((cos(az).* sin(inc)).^2) + sh.*(sin(az).^2).*(sin(inc).^2)+ sv.*(cos(inc).^2); syz = (sH.*-sin(az).*sin(inc).*cos(az))+(sh.*cos(az).* sin(inc).*sin(az))+(sv.*cos(inc).*0); sxz = (sH.*cos(az).* cos(az).*sin(r).*sin(r))+(sh.*sin(az).*cos(inc).*sin(az).*sin(inc))+(sv.*- sin(r).*cos(inc)); sxy =(sH*cos(az)* cos(inc)*-sin(az))+ (sh*sin(az)*cos(inc)*cos(az))+(sv*-sin(inc)*0); sigma_tt = 0.5.*(sx + sy).*(1 +b) - 0.5.*(sx - sy).*(1 + 3.*b).*cos(2.*theta) - sxy.*(1 + 3.*b).*sin(2.*theta);
  3 Commenti
Image Analyst
Image Analyst il 17 Ago 2018
Not sure what the code does. I guess it does something but not what you want.
Please Read this link and format your code.
For what it's worth, I've attached my color wheel demo. Adapt as needed.
HAMZA NASSAR
HAMZA NASSAR il 18 Ago 2018
Is it possible to give me a code format that achieves the same code

Accedi per commentare.

Risposta accettata

Chad Greene
Chad Greene il 18 Ago 2018
It looks like a polar pcolor plot , where color indicates the magnitude of stress?

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