Grouping elements by conditions

I have an array [ 1 1.2 1.5 1.9 5 8 8.1 10 12 12.3 12.5]. I'm trying to group the elements that are within a window of length 1, so I get [ 1 1.2 1.5 1.9] [8 8.1] [12.3 12.5] How can this be done efficiently

[Matt J]

Will the grouped elements always be consecutive?

[dani elias]

how can I use the same concept to group every 4 binary digit, for the case I have an array of 256 binary number,

example

a=[1	1	1	1	1	1	1	1	1	0 1 1 1 0 0 0];  

to be in a form of

b=[1111;1111;1011;1000]

Answer 1

[Matt J]

You could try this file

   x=[ 1 1.2 1.5 1.9 5 8 8.1 10 12 12.3 12.5];
  label = graph_connected_components(abs(x.'-x)<=1)

groupcell = splitapply(@(g){g},x,label)

[Amro Lulu]

WOW, That was fast, thank you so much, it works !

[Matt J]

Will the grouped elements always be consecutive? If so, there are faster ways.

[Amro Lulu]

yes they are always consecutive.

[Amro Lulu]

Hey Matt, I have a question related to this, what if I have a matrix x=[ 1 1.2 1.5 1.9 5 8 8.1 10 12 12.3 12.5; 1 5.3 2.1 5.4 1 6 2.1 45 23 14.3 13.4] And I need to group them the same way, however, only based on the first row, and the resulting group will include the corresponding elements from the second row, as

[ 1 1.2 1.5 1.9; 1 5.3 2.1 5.4] ..etc..

Thank you and I really appreciate it

[Matt J]

Adapting Yuvaraj's answer,

x=[ 1 1.2 1.5 1.9 5 8 8.1 10 12 12.3 12.5; 1 5.3 2.1 5.4 1 6 2.1 45 23 14.3 13.4];
a=x(1,:);
Len=diff([0,find(diff(a)>1),numel(a)]);
  S=mat2cell(x,2,Len)

Answer 2

[Yuvaraj Venkataswamy]

This is your answer.

    X=[ 1 1.2 1.5 1.9 5 8 8.1 10 12 12.3 12.5];
    Len=diff([0,find(diff(a)>1),numel(a)]);
    S=mat2cell(X,1,Len);