how to remove exponential value from a number

If a=4.5236e+15 ,then I want to print the result as b = 4.5236 alone by eliminating the exponential value.How can I do this.Please anyone help me .

[Image Analyst]

Haritha, there is an official "Answers" section below where you can get credit (reputation points) for your answers. Up here, it's supposed to be for people to ask for clarification of the original posting. You might want to consider moving your answer to the Answers section below.

[Rajashree Annapillai]

Exponent is not same throughout the program.It differs accordingly with the input value

[Image Analyst]

But my answer below takes that into account.

Please post your number where my answer below does not work.

Answer 1

[Image Analyst]

Try this:

a = 4.5236e+15
b = a / 10^floor(log10(a))
fprintf('b = %g\n', b)

[Rajashree Annapillai]

Thank you so much sir..Its working...

[Ajin R.]

It works well ! Thanks to Image Analyst. But for negative numbers, it gives complex number as output.

For eg:-

a = -4.5236e+15

b = a / 10^floor(log10(abs(a)))

fprintf('b = %g\n', b)

Output:

b =

3.0227 + 3.3655i

b = 3.02274

Following the answer from Image Analyst, we may rewrite the same as:

a = -4.5236e+15

b = a / 10^floor(log10(abs(a)))

fprintf('b = %g\n', b)

Output:

b =

-4.5237

b = -4.5237

[Image Analyst]

@Ajin R. Not sure what you meant, but the output is not what you said it was. Look:

% First code snippet:
a = -4.5236e+15;
b = a / 10^floor(log10(abs(a)))

b = -4.5236

fprintf('b = %g\n', b)

b = -4.5236

% Second code snippet:
a = -4.5236e+15;
b = a / 10^floor(log10(abs(a)))

b = -4.5236

fprintf('b = %g\n', b)

b = -4.5236