How to permute Permute Vector according to a permutation for its associated labels

Hi, I need to permute a nx3 vector

        251.6147   99.4768  200.1291
          253.8050   94.4682   95.3241
          245.3254  114.3247  255.0000
          ...
according to their associated label, e.g.
1 
2
3
2
3
4
5

with the new permutation being a vector like [5 4 3 2 1] such that 1-->5, 2-->4, 3-->3, 4-->2, 5-->1. There are multiple rows with different values associated to the same label. I would like to associate the first row from old label 1 with the first row from old label 5, then the second row from old label one to second row from old label 5. If there are fewer rows that belong to one label or the other, the next row should be chosen modulo the number of rows that belong to the label --- until the new n*3 vector is "permutated", and filled correctly such that the association of rows to new label ordering holds.

Answer 1

[Kai Berger]

My solution is the following:

function [indicesOut] = permuteIndices(indicesIn,permutation)
%PERMUTEINDICES Summary of this function goes here
%   Detailed explanation goes here
indicesOut=zeros(size(indicesIn));
for i=1:size(permutation,1)
   currIn=find(indicesIn==permutation(i,1));
   indicesOut(currIn)=permutation(i,2);
end
end

and

    function [vecOut,allPositions,maxCountPerLabel,currentLabelPositions] = pernuteVector(vecIn,origLabel,newLabel)
    %PERNUTEVECTOR Summary of this function goes here
    %   Detailed explanation goes here
    maxNumberLabel=max(origLabel(:));
    maxCountPerLabel=[];
    allPositions={};
    for i=1:maxNumberLabel
        allPositions{i}=find(origLabel==i);
        maxCountPerLabel(i)=numel(allPositions{i});

    end
    currentLabelPositions=ones(maxNumberLabel,1);
    for j=1:size(origLabel,1)
       newLabelVal=newLabel(j);
       newLabelPosn=allPositions{newLabelVal};
       newLabelPosCurr=newLabelPosn(currentLabelPositions(newLabelVal));
       currentLabelPositions(newLabelVal)=mod(currentLabelPositions(newLabelVal),maxCountPerLabel(newLabelVal))+1;
       vecOut(j,:)=vecIn(newLabelPosCurr,:); 
    end
    end