create a array base on specific condition ?
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MUKESH KUMAR
il 30 Ago 2018
Commentato: MUKESH KUMAR
il 31 Ago 2018
I had a array like this
A=[0 0 0 10 0 0 0 0 8 0 0 5 0 0 0 3 0 2 0 0 0 1 0 0 0];
and now I want to create a array B like this in which
B(4)=10-8=2;
[B(4)=A(4)-next upcoming non zero value ],
B(9)=8-5=3;[B(9)=A(9)-next non zero value]
and similarly for
B(12)=5-3=2;
B(16)=3-2=1;
B(18)=2-1=1;
B(22)=1;
and rest of the B values are zero. thanks
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Stephen23
il 30 Ago 2018
Modificato: Stephen23
il 30 Ago 2018
>> idx = A~=0;
>> A(idx) = [-diff(A(idx)),1]
A =
0 0 0 2 0 0 0 0 3 0 0 2 0 0 0 1 0 1 0 0 0 1 0 0 0
5 Commenti
Stephen23
il 31 Ago 2018
Modificato: Stephen23
il 31 Ago 2018
@MUKESH KUMAR: you get negative values because although in your question you gave values which decrease in magnitude (so their differences are all positive), in your real A data all of the values increase in magnitude (so their differences are all negative). Lets have a look at some of the values:
>> B(find(B))
ans =
-1
-5
-3
-2
... lots more here
-3
-2
1
>> A(find(A))
ans =
1
2
7
10
12
13
... lots more here
128
131
133
In your question you wrote: "I had a array like this"
A=[0 0 0 10 0 0 0 0 8 0 0 5 0 0 0 3 0 2 0 0 0 1 0 0 0];
"and now I want to create a array B like this in which"
B(4)=10-8=2;
[B(4)=A(4)-next upcoming non zero value ],
B(9)=8-5=3;[B(9)=A(9)-next non zero value]
Lets try your exact calculation method with the real A values:
B(6334) = A(6334) - A(6478) = -1
B(6478) = A(6478) - A(7487) = -5
B(7487) = A(7487) - A(7543) = -3
...etc
All are negative, all follow the method that you gave in your question, and all are exactly the values that are in B.
Più risposte (1)
jonas
il 30 Ago 2018
v=A(find(A~=0));
vid=find(A~=0);
B=A
B(vid)=B(vid)-[v(2:end) 0]
not the most elegant solution
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