How to avoid 'Index in position 1 is invalid.'

1 visualizzazione (ultimi 30 giorni)
AelinAG
AelinAG il 11 Set 2018
Risposto: Image Analyst il 11 Set 2018
If I ask matlab to give me for example A(i - 1, j - 1) and A(i, j + 1) if matrix A and indices i, j are given, and one of them doesn't exist(because 'Index in position 1 is invalid'), how do I ignore the element that doesn't exist but print the other element(s)? For example, is there a function to test if those elements exist? Thanks!

Risposte (1)

Image Analyst
Image Analyst il 11 Set 2018
Well you could let it throw an error. Or you could detect it in advance and throw a "friendlier" error
[rows, columns] = size(A);
row = i - 1; % Whatever....
col = j + 1;
if row < 1 || row > rows
warningMessage = sprintf('Error for i=%d, i-1 would give a row outside the range [1, %d], i, rows);
uiwait(errordlg(warningMessage));
end
if col< 1 || col > columns
warningMessage = sprintf('Error for j=%d, this would give a column outside the range [1, %d], j, columns);
uiwait(errordlg(warningMessage));
end
Or something similar. Or you could clip the values to the valid range.
row = max(1, i-1);
row = min(row, rows);
col = max(1, j-1);
col = min(col, columns);

Categorie

Scopri di più su Startup and Shutdown in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by