What is f ? And how big is it?
How to fix index in a parfoor loop?
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Andreu Angles Castillo
il 13 Set 2018
Commentato: Andreu Angles Castillo
il 18 Set 2018
I have the following code and get indexing error
parfor dt=0:round(tmax/step)
fprintf(1,'\b\b\b\b\b%05.2f',dt);
for dm=0:dt
A(dm+1,dt+1) = f(dm,dt);
end
end
It does not make sense, for me, because each loop of the first for is stand alone in the variable dt. The size of A has been prefixed.
The error messages on the script are:
-The PARFOOR loop cannot run due to the way varaiable 'A' is used. (On line 1)
-Valid indices for 'A' are resticted in PARFOR loops. (On line 4)
Error when run:
Error: The variable A in a parfor cannot be classified. See Parallel for Loops in MATLAB, "Overview".
4 Commenti
Stephen23
il 13 Set 2018
@Andreu Angles Castillo: please give the complete error message. This means all of the red text.
Risposta accettata
Titus Edelhofer
il 14 Set 2018
Hi Andreu,
agreed, it looks as if this case could be handled. But it is fairly easy to work around this by separating the inner loop from the parfor loop:
n = round(tmax/step) + 1;
parfor dt=0:round(tmax/step)
fprintf(1,'\b\b\b\b\b%05.2f',dt);
col = zeros(n, 1);
for dm=0:dt
col(dm+1) = f(dm, dt);
end
A(:, dt+1) = col;
end
Titus
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!