Listing possible combinations of integers, given constraints (Gear Ratio Related)
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The problem:
Let Gear Ratio = ( 1 + N3/N1 )/( 1 - ( ( N3*N4 )/( N5*N2) ) ), where N1, N2, ..., N5 must be integers. I'm looking to list combinations of N1, N2, ..., N5 that make the gear ratio fall within a specified range (i.e. 50 - 60), with upper limits to what the values of N1, N2, ..., N5 can be (i.e. 150).
I've done it using a for loop then and listing / filtering values that are within the given constraints, but am looking for a more efficient solution given that the for loop takes forever to finish.
I looked into using ndgrid from the following example: https://www.mathworks.com/matlabcentral/answers/308775-integer-division-problem-gear-ratio-related
But the arrays created would be much too large.
Any ideas / hints would be appreciated!
2 Commenti
Walter Roberson
il 13 Set 2018
How does the equation distinguish between N2 and N5? Exchanging them does not change anything. You could create
[p, q] = ndgrid(1:150);
N25 = unique(p.*q);
And use N25 in calculation of the basic ratios, later substituting all N2 N5 pairs that multiply to that particular value.
Risposte (1)
Aquatris
il 13 Set 2018
Modificato: Aquatris
il 13 Set 2018
One possibility is using an optimization. Here is a simple code for it using OPTI toolbox;
clear all,clc
% round() is used to enforce integer value
gr = @(N) (1+round(N(3))/round(N(1)))/(1- round(N(3))*round(N(4))/round(N(5))/round(N(2))));
% initial guess
x0 = [1 2 3 7 11]';
% lower and upper bounds for N = [N1 N2 N3 N4 N5]'
lb = zeros(5,1);
ub = ones(5,1)*150;
% Nonlinear Constraints for desired gear ratio range(cl <= nlcon(x) <= cu)
nlcon = @(x) gr(x);
cl = [50];
cu = [90]; % upper is chosen 90 cause initial guess give 88
% formulate the problem in OPTI toolbox
Opt = opti('fun',gr,'bounds',lb,ub,'x0',x0,'nl',nlcon,cl,cu)
[x,fval,exitflag,info] = solve(Opt); % this will try to minimize the
% gr function and since the lower
% limit is defined as 50, it will
% give a gear ratio close to 50
% if optimization is succesful
N_solution = round(x) % the necessary [N1 N2 N3 N4 N5]' = [2 2 3 7 11]'
gear_ratio = gr(N_solution) % achieved gear ratio = 55
The problem can be formulated in a similar manner for built-in Matlab function as well.
3 Commenti
Aquatris
il 13 Set 2018
An alternative method would be a brute-force search as;
sol = [];
for n1 = 1:150
for n2 = 1:150
for n3 = 1:150
for n4 = 1:150
for n5 = 1:150
e = gr([n1 n2 n3 n4 n5]);
if(e < 60 & e > 50)
sol = [sol;n1 n2 n3 n4 n5];
end
end
end
end
end
end
where gr is the function from the answer I gave and each row of sol variable is a combination that would achieve desired gear ratio.
I ran the above code for 240 sec. and terminated it. It did not even reach n1 = 2 (it was at n1=1,n2=13,n3=21,n4=47,n5=134) but was able to find 150k possible combinations. So I do not think it is feasible to find all the combinations of n1 n2 n3 n4 n5 that give the desired gear ratio for your problem since I think there are billions of possible combinations.
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