i have a 48*48*3 matrix , i want to convert it to 48*48 matrix where each element of the matrix will show a list of 3 characters in a cell. how to do it?

for eg-

i need this matrix to look like {1,9} {2,7} {3,8}.......

[Image Analyst]

Your desired output: {1,9} {2,7} {3,8}....... does not show a "list of 3 characters in a cell". It shows a list of the first and last element (2 numbers, not 3 characters) for every (row, col) location. So which is it? Do you want 2 numbers or 3 characters?

[shashwat soni]

3 characters

[Image Analyst]

Is it a character array, or a numerical array?

Answer 1

[Image Analyst]

For all the numbers, you can try this:

[rows, columns, numSlices] = size(m);
index = 1;
ca = cell(1, rows*columns); % Preallocate
for row = 1 : rows
    for col = 1 : columns
        ca{index} = m(row, col, :);
        index = index + 1;
    end
end

Answer 2

[Matt J]

Acell=cellfun( @(c) c(:).',  num2cell(A,3),   'uni',0 );

[Andrei Bobrov]

+1

Answer 3

[Image Analyst]

Did you try something like this:

[rows, columns, numSlices] = size(m);
index = 1;
ca = cell(1, rows*columns); % Preallocate
for row = 1 : rows
    for col = 1 : columns
        ca{index} = [m(row, col, 1), m(row, col, end)];
        index = index + 1;
    end
end