how to calculate the convolution of two signal without using CONV() ?
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Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
4 Commenti
Image Analyst
il 25 Set 2018
For 1-D convolution, you need two for loops, one inside the other. What does "show on a plot the process" mean? What exactly are you going to plot? Why do you need to plot anything anyway? Is this homework? Why not simply use conv() and not do all this complicated, unnecessary stuff? (Actually the convolution is not that hard if you'd just try it.) What do you mean by "two guides"? Do you have 1 fig file, or two?
Synchro_mdn
il 25 Set 2018
Image Analyst
il 25 Set 2018
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
Synchro_mdn
il 25 Set 2018
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Più risposte (5)
Manoj Manu
il 16 Ago 2021
1 voto
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
1 Commento
Royston Mendonca
il 24 Gen 2022
what exactly is '-b^', '-ro' and '-ms' ?
Sk Group
il 25 Ott 2021
1 voto
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output
For complete detailed post visit: https://www.swebllc.com/convolution-without-function-in-matlab/
Kiran K V
il 28 Giu 2022
1 voto
clear all;
clc;
x = input ('Enter the first signal/sequence ');
h = input('Enter the second signal/sequence ');
Find the length of the individual signals, and thus the output
[~,L]= size (x);
[~,M] = size (h);
len y = L + M - 1
y = zeros (1, len_y);
len = 1:1en_y;
for i = 0 / l * eny
for j = 0/1 * eny
if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);
end
end
end
disp (y)
stem (len, y)
1 Commento
Or Baron
il 31 Lug 2022
what do you mean by y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1); ? what does ,^ mean?
Muhammad
il 27 Ago 2023
0 voti
1 2 3
-1 2 3
Mehmet Eren Dikmen
il 28 Mar 2024
0 voti
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent
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