how to calculate the convolution of two signal without using CONV() ?

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Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
  4 Commenti
Image Analyst
Image Analyst il 25 Set 2018
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
Synchro_mdn
Synchro_mdn il 25 Set 2018
Lets leave out that part, I just really need to know how to set the for loop for two different signal.

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Risposta accettata

Dimitris Kalogiros
Dimitris Kalogiros il 25 Set 2018
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
  3 Commenti
Allard Quek
Allard Quek il 12 Mar 2022
the first characters represent the colour and the second characters represent the shape:
'-b^': blue triangle
'-ro': red circle
'-ms': magenta square

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Più risposte (5)

Manoj Manu
Manoj Manu il 16 Ago 2021
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');

Sk Group
Sk Group il 25 Ott 2021
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output

Kiran K V
Kiran K V il 28 Giu 2022

clear all;

clc;

x = input ('Enter the first signal/sequence ');

h = input('Enter the second signal/sequence ');

Find the length of the individual signals, and thus the output

[~,L]= size (x);

[~,M] = size (h);

len y = L + M - 1

y = zeros (1, len_y);

len = 1:1en_y;

for i = 0 / l * eny

for j = 0/1 * eny

if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);

end

end

end

disp (y)

stem (len, y)


Muhammad
Muhammad il 27 Ago 2023
1 2 3
-1 2 3

Mehmet Eren Dikmen
Mehmet Eren Dikmen il 28 Mar 2024
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent

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