How to generate numbers from probability mass function?
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    Clarisha Nijman
      
 il 9 Ott 2018
  
    
    
    
    
    Risposto: PARTHEEBAN R
 il 22 Mag 2021
            Hallo,
Given a probability mass function defined as P(X=3)=0.2, P(X=7)=0.3 and P(X=10)=0.5, I want to generate randomly 30 numbers (values for X) with this probability mass function as base. But I really have no idea how and where to start.
Can somebody help me?
Thank you in advance
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  Torsten
      
      
 il 9 Ott 2018
        
      Modificato: Torsten
      
      
 il 9 Ott 2018
  
      n = 30;
X = zeros(n,1);
x = rand(n,1);
X(x <= 0.5) = 10;
X(x > 0.5 & x <= 0.8) = 7;
X(x > 0.8) = 3;
3 Commenti
  Torsten
      
      
 il 10 Ott 2018
				For an explanation, see
https://stats.stackexchange.com/questions/26858/how-to-generate-numbers-based-on-an-arbitrary-discrete-distribution
Più risposte (3)
  Bruno Luong
      
      
 il 9 Ott 2018
        A more generic method:
p = [0.2 0.3 0.5];
v = [3 7 10];
n = 10000;
c = cumsum([0,p(:).']);
c = c/c(end); % make sur the cumulative is 1 
[~,i] = histc(rand(1,n),c);
r = v(i); % map to v values
  Jeff Miller
      
 il 20 Ott 2018
        3 Commenti
  Jeff Miller
      
 il 20 Ott 2018
				Did you download the Cupid files (see the link in my answer)? These define the List class (which handles the cumulative distribution behind the scene). Do the other Cupid demos run correctly?
Well, Cupid may be overkill for your problem, but it does have a lot of flexibility.
  PARTHEEBAN R
 il 22 Mag 2021
        A random variable X has cdf F(x) = { 0 , if x < − 1 a(1 + x ) , if − 1 < < 1 1 , if x ≥ 1 . Find (1) the value of a, (2) P(X > 1/4 ) and P ( − 0 . 5 ≤ X ≤ 0 ) .
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