viewSolid is not working

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Ravi Prakash
Ravi Prakash il 14 Ott 2018
Commentato: Steven Lord il 18 Set 2025 alle 13:41
Its not working in my Matlab app.Its showing invalid function.What can i do

Risposte (2)

Walter Roberson
Walter Roberson il 14 Ott 2018
  2 Commenti
Tansheed
Tansheed il 21 Dic 2023
I did download it and moved it into the same file with the matlab files just as my lecturer instructed me to do. But it still shows invalid to me but in my peers comupters it succesfully executes the action
Tansheed
Tansheed il 21 Dic 2023
Please tell us the possible reasons and how to slove them

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ATHUL N
ATHUL N il 18 Set 2025 alle 13:31
clc;
clear all;
syms x y z
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
Error using sym/int (line 128)
Too many arguments.
viewSolid(z,0,1+x+y,y,0*x,sqrt(x),x,0,1);
  1 Commento
Steven Lord
Steven Lord il 18 Set 2025 alle 13:41
This line of code (commented out so I can run other commands later in the comment) is not syntactically valid, as it has three ( and two ). I assume you ran it and then deleted one of the closing parentheses. Where was that closing parenthesis? Was it at the end of the line?
%{
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
%}
If it was, the inner call to int looks fine. [Since z doesn't appear in 6*x*y, you're integrating a constant.]
syms x y z
innerIntegral = int(6*x*y, z, 0, 1 + x + y)
innerIntegral = 
If you're trying to perform a triple integral, the innermost one over z, the middle one over y, and the outermost over x, you're missing two closing parentheses and an extra int( call.
middleIntegral = int(innerIntegral, y, 0, sqrt(x))
middleIntegral = 
outerIntegral = int(middleIntegral, x, 0, 1)
outerIntegral = 
Or putting them all together in one line:
% Added vvvv v v
value = int(int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x)),x,0,1)
value = 

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