how to formulate logical matrix in a loop?
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Shubham Mohan Tatpalliwar
il 24 Ott 2018
Commentato: Andrei Bobrov
il 25 Ott 2018
i am having a matrix and want to separate them in the depending on its value
A=[1,2,3,4,5,6,7,8,9,10]
expected result are
idx1=[1,0,0,0,0,0,0,0,0,0] % for 1
...
idx10=[0,0,0,0,0,0,0,0,0,1] % for 10
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Andrei Bobrov
il 25 Ott 2018
A = 1:10;
idx = A(:) == A(:)'
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Andrei Bobrov
il 25 Ott 2018
what should i change to have a 5 rows with a step of 2
?
A = 1:2:10;
idx = A(:) == A(:)';
Più risposte (1)
madhan ravi
il 24 Ott 2018
Modificato: madhan ravi
il 24 Ott 2018
A=[1,2,3,4,5,6,7,8,9,10]
RESULT = zeros(1,numel(A));
RESULT1= RESULT;
for i = 1:numel(A)
idx(i)=A(i)==1;
idx1(i)=A(i)==10;
end
RESULT(idx) = A(idx)
RESULT1(idx1) = A(idx1)
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