How to get three sub matrices from a matrix of any order? How we will do for general matrix? I have given an example of order 5.

For example:

A=  [1    4    5    7    8;
     4    2    6    9    10;
     5    6    3    1    1;
     7    9    1   3    5;
     8    10   1    5   4];

Ist sub matrix is A11=[1 4 5; 4 2 6 ; 5 6 3]; order should be 3by3,

2nd sub matrix is B11=[7 9 1; 8 10 1]; order should be 2by3,

3rd sub matrix is C11=[3 5; 5 4]; order should be 2by2.

[Walter Roberson]

What is the rule for the placement and sizes of the sub-matrices?

For example why is C11 taken from A(end-1:end, end-1:end) instead of (say) from A(1:2, end-1:end)

[Farooq Aamir]

@ Walter Roberson, A has some special structure so that's why I divide A into this way. (e.g Hamiltonian matrix)

[Walter Roberson]

If it had been order 7 then which parts would you need?

Answer 1

[madhan ravi]

A=  [1    4    5    7    8;
     4    2    6    9    10;
     5    6    3    1    1;
     7    9    1   3    5;
     8    10   1    5   4];

A11=a(1:3,1:3)
B11=a(1:3,end-1:end)
C11=a(end-1:end, end-1:end)

[Farooq Aamir]

@ Madhan Ravi bundle of thanks....

[madhan ravi]

Anytime :)