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I have 468 by 1 matrix of floating data. I need to convert it to binary with same dimensions, e.g., 468 by 1. Kindly help

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-1.9836
-0.0287
-0.4330
0.7517
-0.4883
-0.1712
0.2263
0.7347
.... 400+ rows here
-0.5308
-0.5600
-0.5302
-0.3920
-0.0819
-0.3893
-0.6267
0.0062
-0.2508
0.8580
0.2292
0.0196
-1.3797
-0.6845
-0.2160
convert it binary with same matrix dimensions
  3 Commenti
Stephen23
Stephen23 il 7 Nov 2018
Modificato: Stephen23 il 7 Nov 2018
@Guilalume: well, the numeric data shown in the question is already a binary array, and seems to fulfill all of the requirements so far. Perhaps the question was asked without realizing that numeric arrays are already binary...
Guillaume
Guillaume il 7 Nov 2018
Yes, I think it's a case of the OP not knowing what binary is. However, considering the complaint that Kalyan's answer generates an 8 column matrix, it does look like the OP is after a column vector of 0 and 1.

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KALYAN ACHARJYA
KALYAN ACHARJYA il 7 Nov 2018
Modificato: KALYAN ACHARJYA il 7 Nov 2018
Hope this is helpful, for example
a=[-1.23;-2.54;-1.50]
a =
-1.2300
-2.5400
-1.5000
>> d=dec2bin(typecast(int8(a),'uint8'))
d =
11111111
11111101
11111110
  7 Commenti
James Tursa
James Tursa il 7 Nov 2018
Modificato: James Tursa il 7 Nov 2018
You need to give us an explicit example of what you mean by a "double binary" type. Technically, MATLAB stores the double value in floating point binary already, so what is it that you actually want? E.g., if the double value is 1.5 then what would be your desired output?
Stephen23
Stephen23 il 7 Nov 2018
Modificato: Stephen23 il 7 Nov 2018
@Sajid Sarwar: I guess you did not read my request. Here is what I asked you:
Please give us an example of a "double(binary) value". Show us one.

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