Minimum value with row index
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I wrote the following code to get a minimum positive value and the row index as well but the output is giving wrong row index. Anyone can help me?
The answer should be...minba=0.005 ri=9
clc; clear all;
ba=[52 15 52 44 44 0 -25 -4 .05]; [minba ri]=min(ba((ba>0)))
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Sean de Wolski
il 29 Mar 2011
idx = min(find(ba==minba))
2 Commenti
Matt Fig
il 29 Mar 2011
I understand the question to be "How do I find the minba and ri," not, "Given, minba, how to find the ri?"
Più risposte (2)
Matt Fig
il 29 Mar 2011
If minba is not known before hand (the general case, and what it sounds like you want to have), then:
ba = [52 15 52 44 44 0 -25 -4 .05]; % Your data...
ba(ba<=0) = inf; % Take non-positive values out of the picture.
[minba,ri] = min(ba) % Find the min and index.
minba =
0.05
ri =
9
A faster alternative to the above, if the number of non-positives is a large fraction of the whole:
minba = min(ba((ba>0)));
ri = find(ba==minba,1);
3 Commenti
Matt Fig
il 29 Mar 2011
How would you use FIND if minba wasn't known before hand? I think anything that could do this using FIND would be slower than what I showed...
Matt Fig
il 29 Mar 2011
But I was wrong. This is faster indeed, when the number of non-positives is a large fraction of the whole:
minba = min(ba((ba>0)));
ri = find(ba==minba,1);
Walter Roberson
il 29 Mar 2011
idx = find(ba > 0,1);
minba = ba(idx);
5 Commenti
Matt Fig
il 29 Mar 2011
@Walter
Qouting the OP (without quotes of course)
I wrote the following code to ...
The answer _should_ _be_...minba=0.005 ri=9
So I assume Mohammad wanted to be shown the _correct_ way to get both minba and ri.
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