How made the code as easy?

P=[1 32 3 78 5 6 7 8 9 10] ;P is my original array which has the size is 1*10; I have Q=[2 4 7];I want delete in Q array value in P array; My expect output is P=[ 1 3 5 6 8 9 10] by using for loop only because of the size of Q array may be change ;P(:,[Q(1) Q(2) Q(3)])=[] this command use only the size of Q array is 1*3 .So I need for loop logic which is common of any array size.

Answer 1

[madhan ravi]

P(Q)=[] %edited after Jan's comment

[VIJAY]

Great ...

[madhan ravi]

Anytime :) @vijay

[madhan ravi]

@stephen the OP want to delete the value of P where the Q value corresponds to the index of P , please before commenting read the question properly and comment

P=[1 32 3 78 5 6 7 8 9 10]

in the above P array can you find the value 2???

My expect output is P=[ 1 3 5 6 8 9 10]

2 in Q corresponds to index value 32 in P

4 in Q corresponds to index value 78 in P

7 in Q corresponds to index value 7 in P which needs to be deleted

[Steven Lord]

I interpreted the question the way madhan ravi did. I believe Q contains the indices of the elements in P that should be deleted, not the elements in P that should be deleted.

If VIJAY wanted the latter, I would use setdiff with the 'stable' flag to remove all instances of elements in Q from P, or find to locate just the first (or last) instance in P of each element in Q and delete those locations.

[madhan ravi]

The question is badly framed

[madhan ravi]

Thank you very much @Steven lord for justifying my answer

[Stephan]

I agree the question is unclear. Since it is accepted i will remove flag. Perhaps next time ask the OP to clarify....

[madhan ravi]

and remove your comments @stephen

[Stephan]

I think we are clean now ;-)

+1

[madhan ravi]

Thank you @stephen :)

[Stephan]

No problem

[Jan]

You can omit the square brackets and 1:end :

P(Q)=[]

[madhan ravi]

+1 @Jan cool

Answer 2

[Stephan]

If you want to delete the values at the indicies in P, that are specified in Q use the answer from Madhan above. If you need to delete the values in P specified in Q use:

P(ismember(P,Q))=[]

[madhan ravi]

+1 another way of approach