Problem with GUI Checkbox Handles in Matlab

I have write a code using GUI to get the values from two Checkboxes and plot the results.

Variables are Gain and PT. Handles from Check boxes are handles.cbox_LG & handles.cbox_LG_PT_15.

I have initated the Handles in GUI and set the

handles.cbox_LG = get(hObject,'Value');

guidata(hObject,handles) in the Callback.

Then i add the Run Push Button to send the function in the main program and in this Main, i use follwoing IF statement.

if (Gain == 1 && PT == 1 && handles.cbox_LG == 1 && handles.cbox_LG_PT_15 == 1)

But the Matlab gives the error with

"Reference to a cleared variable handles.

Error in S_Curve_Test (line 90)

if (Gain == 1 && PT == 1 && handles.cbox_LG == 1 && handles.cbox_LG_PT_15 == 1)||(Gain == 1 && PT == 2 && handles.cbox_LG == 1 && handles.cbox_LG_PT_25 == 1)"

Please provide the remedy for this fault.

[Luna]

when you run the code, do you close the figure window which contains your checkboxes?

“reference to deleted object handle” error might be occured because of that.

I recommend you to assign your handles.checkbox value into different variable or another property of your gui class object. because when a figure deleted or closed all children’s handles are deleted, too.

[Rik]

There is a subtle difference here: cleared variable or deleted object.

It seems the handles variable does not yet exist at that point in the code. Can you attach your function? Posting it in a comment is not the best way to go, as GUIDE generates horrible code that is too long to have a good look in this forum layout.

[Mohsin]

@Luna.. can you guide me where can i assign handles?

[Mohsin]

@Rik Wisselink, Please find the attachment for the functions.

Answer 1

[Walter Roberson]

you clearvars as the first thing inside your function. When you do that the names associated with the parameter list continue to exist for name resolution purposes but they are marked as being associated with a cleared variable .

The only reason to have a clearvars as the first statement inside a function is in order to deliberately provoke odd behavior like you are observing , so we must conclude that the code is acting exactly as it was designed to act.

[Mohsin]

Thanks @Walter. Problem is solved.