How to choose values ​​in the second and third column corresponding to the drawn numbers?

   %N X Y        
AA=[ 1 0 4
2 1 5 
21 4 6
81 3 7
92 7 8
73 6 4
65 3 3
36 5 4 
16 6 5
6 7 4]

A=AA(:,1);
disp(A);
b=(A(randperm(size(A,1),3),1))
disp(b);
% How to choose values ​​in the second and third column corresponding to the drawn numbers?
for i=1:3 %This solution give me error - Index in position 1 exceeds array bounds (must not exceed 10).
    c=b(i,1);
    disp(AA(c,2));
    disp(AA(c,3));
end

Answer 1

[Arunkumar M]

Error occurs because with c you are finding the element which is a part of first column in AA. But this element is not the index. So you have to find the index where it is located and then pull out second and third column values.

for i=1:3 
    c=b(i,1);
    temp1 = find(A == c);
    temp2 = temp1(1,1); % in case multiple values are returned in temp1.
    disp(AA(temp2,2));
    disp(AA(temp2,3));
end

[hawk5577]

Error:

Index in position 1 exceeds array bounds.

Error in smiec4 (line 22)

temp2 = temp1(1,1); % in case multiple values are returned in temp1.

[Arunkumar M]

Is temp1 empty?

Answer 2

[Bruno Luong]

Why make so complicated? RANDPERM returns the position, store and use it rather than trying to recover it.

AA=[ 1 0 4
2 1 5 
21 4 6
81 3 7
92 7 8
73 6 4
65 3 3
36 5 4 
16 6 5
6 7 4]

p = randperm(size(A,1),3);
b = AA(p,1)
AA(p,:)