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Adding sparse matrices efficiently?

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Hi, I have a cell array which consists of many sparse matrices. For example:
N.B. In my original problem each sparse matrix is about 4000*4000 in size and has many zero entries
A{1}=sparse(magic(150));
A{2}=sparse(magic(150));
A{3}=sparse(magic(150));
A{4}=sparse(magic(150));
....
% I want something like:
KK = A{1}+A{2}+A{3}+....
% KK should be a sparse matrix of 150*150
% Adding them in a loop is very time consuming
% I tried the following but did not work:
KK = sum(cat(2,KC{:}),3); % or 1,2 as the sum dimension
% also
KK = sum([KC{:}]); % gives a vector
  2 Commenti
David Goodmanson
David Goodmanson il 17 Nov 2018
Hi Mohammod,
It's not going to be a good idea to use sparse(magic(N)) as a benchmark for timing. This matrix is stored in the sparse convention but is absolutely not sparse, since it has no nonzero elements at all. Sparse has to do a lot of work in that case.
sparse(magic(N)) + sparse(magic(N)) takes more time than the addition of the full matrices, magic(N) + magic(N).
Mohammod Minhajur Rahman
Mohammod Minhajur Rahman il 17 Nov 2018
Hi David, I am sorry to put it in that way, in my original problem the size of each sparse matrix is 4000*4000 and it has many zero entries. The comment that I have added that it takes huge time based on the original scenario

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James Tursa
James Tursa il 17 Nov 2018
In general, everytime you add two sparse matrices together a bunch of sparse index sorting etc has to take place first and then the result of the additions gets put into new memory. Doing this at each iteration is what is slowing you down.
If your matrices are only 4000x4000, then maybe adding the individual matrices into a full matrix would be faster since there wouldn't be any need to sort the combined indexes or to put the result into new memory. You could try two different options with this approach.
1) Start with a full 0's matrix and add your sparse matrices into it. A good underlying algorithm will simply add the sparse stuff into the full matrix at the appropriate spots without any index sorting needed. So:
result = zeros(4000,4000);
for k=1:whatever
result = result + A{k};
end
result = sparse(result);
2) Do the equivalent of the above inside a mex routine. That way you could ensure that no large extraneous data copying was taking place, but everything was simply added directly into the result. This mex routine would not be too difficult to write. If you opt for this method let me know and I can help.
  3 Commenti
Jin Yang
Jin Yang il 16 Lug 2020
James, thank you for this answering! Is there anything we need to take care to write a c mex file with cell data?
James Tursa
James Tursa il 16 Lug 2020
Modificato: James Tursa il 16 Lug 2020
Nothing special needed. Just pass in the cell array, create the full array inside the mex routine, and write a loop that does the adding. You could sparse the end result either inside or outside the mex routine.

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Più risposte (1)

Bruno Luong
Bruno Luong il 17 Nov 2018
Modificato: Bruno Luong il 17 Nov 2018
The fatest way to add sparse matrices is to build the sum from scratch.
It takes 4 second for 1000 random matrices of 4000x4000 with density 1e-3.
I = [];
J = [];
V = [];
n = 0;
for k = 1:length(A)
[i,j,v] = find(A{k});
p = n + numel(i);
m = numel(I);
if p > m
m = max(p,2*m);
I(m) = 0;
J(m) = 0;
V(m) = 0;
end
idx = (n+1:p);
I(idx) = i;
J(idx) = j;
V(idx) = v;
n = p;
end
idx = (n+1:numel(I));
I(idx) = [];
J(idx) = [];
V(idx) = [];
[m,n] = size(A{1});
SUM = sparse(I,J,V,m,n)
  1 Commento
Mohammod Minhajur Rahman
Mohammod Minhajur Rahman il 19 Nov 2018
Hi Bruno, thanks for your suggestion, I did implement your code in my settings and it gives perfect results. I don't know why but in my current code setting, starting with a 0's matrix results in faster to solve this.

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