finding the mean and max
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    johnson saldanha
 il 21 Nov 2018
  
    
    
    
    
    Modificato: Andrei Bobrov
      
      
 il 21 Nov 2018
            suppose i have a matrix where the first column is x(:,1)=[ 1 1 1 2 2 1 1 3 1 ] and second column is x(:,2)=[ 2 3 2 4 6 9 7 8 9];
i want the output as y(:,1)=[ 1 2 3 ],  y(:,2)=[ 9 6 8] and y(:,3)=[5.33  5  8];
the first column should be the values from first column of x reduced to a single value and in ascending order, the second column should be the highest number from the second column of x for a particular value in first input column. for ex. for all the 1's in first column of x should return one max value from the second column of x. the third column should contain the means of the second column of x for a particular value in first column of x. same example as given. 
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  Rik
      
      
 il 21 Nov 2018
        
      Modificato: Rik
      
      
 il 21 Nov 2018
  
      The first column you can achieve with unique, the second and third can be done with accumarray.
x=[ 1 1 1 2 2 1 1 3 1 ; 2 3 2 4 6 9 7 8 9]';
[col1,~,ind]=unique(x(:,1));
col2=accumarray(ind,x(:,2),[],@max);
col3=accumarray(ind,x(:,2),[],@mean);
y=[col1 col2 col3]
3 Commenti
  Walter Roberson
      
      
 il 21 Nov 2018
				the third output of unique gives you information about the original order . 
  Rik
      
      
 il 21 Nov 2018
				This code produces the output like you describe. As Walter mentions (and as you can read in the doc of unique) the third output of the unique function returns the order so isequal(col1(ind),x(:,1)) returns true (barring any float rounding errors).
This means that this input will also work as intended:
x=[5 1 1 1 2 2 1 1 3 1 5;9 2 3 2 4 6 9 7 8 9 1]';
Più risposte (1)
  Andrei Bobrov
      
      
 il 21 Nov 2018
        
      Modificato: Andrei Bobrov
      
      
 il 21 Nov 2018
  
      EDITED
>> XXX =[ 1 1 1 2 2 1 1 3 1 ; 2 3 2 4 6 9 7 8 9]'
XXX =
     1     2
     1     3
     1     2
     2     4
     2     6
     1     9
     1     7
     3     8
     1     9
>> T = varfun(@(x)[max(x),mean(x)],array2table(XXX),'G',1);
out = T{:,[1,3]}
out =
            1            9       5.3333
            2            6            5
            3            8            8
>> 
2 Commenti
  Andrei Bobrov
      
      
 il 21 Nov 2018
				
      Modificato: Andrei Bobrov
      
      
 il 21 Nov 2018
  
			I edited my answer, and you read the help about the MATLAB functions.
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