assign the same vector to be the same cell

Let's say, I have the matrix:

A=[x,y]=[1 2;1.1 2;1.2 2;1 3;1.1 3;1.2 3;1 4;1.1 4;1.2 4];

If i wanna group all vector having the same value of y coordinate. How can I do that?

Example, the result like that:

Cell1=[1 2

1.1 2

1.2 2]

Cell2=[1 3

1.1 3

1.2 3]

Cell3=[1 4

1.1 4

1.2 4]

[madhan ravi]

People here put some efforts to help you and you mercilessly close the question without clarifying how rude

[ha ha]

@ madhan ravi . I'm very sorry. I think I misclick on the button. Very sorry for my mistake.

Answer 1

[madhan ravi]

A=[1 2;1.1 2;1.2 2;1 3;1.1 3;1.2 3;1 4;1.1 4;1.2 4]';
group=reshape(A,2,3,3);
CELL=cell(1,3);
for i = 1:size(group,3)
CELL{i}=group(:,:,i)';
end
celldisp(CELL)

command window:

>> 
 
CELL{1} =
 
    1.0000    2.0000
    1.1000    2.0000
    1.2000    2.0000

 
 
CELL{2} =
 
    1.0000    3.0000
    1.1000    3.0000
    1.2000    3.0000

 
 
CELL{3} =
 
    1.0000    4.0000
    1.1000    4.0000
    1.2000    4.0000

 
>> 

[ha ha]

@ madhan ravi. Why did you know I have 3 cell? I think, you use number "3", because you observe there are 3 cell by visualization. But In general case, we can not know how many cell.

Answer 2

[Andrei Bobrov]

Cell = mat2cell(A,accumarray(findgroups(A(:,2)),1),size(A,2));

Answer 3

[Guillaume]

Can be done easily with findgroups (or the older unique) and splitapply (or the older accumarray), in just one line:

A = [1 2;1.1 2;1.2 2;1 3;1.1 3;1.2 3;1 4;1.1 4;1.2 4];
C = splitapply(@(rows) {A(rows, :)}, (1:size(A, 1))', findgroups(A(:, 2)));
celldisp(C)

with unique and accumarray, you need two lines as you need the 3rd return value of unique:

A = [1 2;1.1 2;1.2 2;1 3;1.1 3;1.2 3;1 4;1.1 4;1.2 4];
[~, ~, id] = unique(A(:, 2));
C = accumarray(id, (1:size(A, 1))', [], @(rows) {A(rows, :)});
celldisp(C)