Why do I receive the error "Inavlid file identifier" when using fopen?

2 visualizzazioni (ultimi 30 giorni)
function spec = abc(filelist);
filelist='filelist23.txt';
fl = importdata(filelist);
nFile = size(fl,1);
%fid = fopen(file);
Nbins = 1024;
spec = zeros(nFile, Nbins);
for iFile = 1:nFile
fid=fopen(fl{iFile})
% Read the 18 header text lines (but not the entire line, and discard)
for i=1:18 hdr=textscan(fid,'%s %*[^\n]',1); end
x=textscan(fid,'%d%d','delimiter',',,');
x = x{:,1};
x = reshape(x,2,Nbins);
spec(iFile,:) = x(2,:);
fclose(fid);
end
end
I get an error at fopen--I get the number -1 which is inccorect and i have no idea how to fix it. The error message is:
??? Error using ==> textscan
Invalid file identifier. Use fopen to generate a valid file identifier.
Error in ==> rdUCS30MCA at 23
for i=1:18 hdr=textscan(fid,'%s %*[^\n]',1);
  2 Commenti
Jan
Jan il 16 Lug 2012
Not nice, Leah. You found out that you cannot delete a thread after somebody has answered. Then you decided to overwrite the text by nonsense. This is a misuse of the idea of a public forum.
Randy Souza
Randy Souza il 18 Ott 2012
I restored the original question based on Lucas' assertion that this question might help others.

Accedi per commentare.

Risposte (2)

Jan
Jan il 10 Lug 2012
Every fopen() should be accompanied by a check of the results:
fid = fopen(fl{iFile});
if fid == -1
error('Author:Function:OpenFile', 'Cannot open file: %s', fl{iFile});
end
File access is prone to problems. A stable program catchs them and the time wasted by debugging can be reduced, if an exhaustive error message is displayed.

Image Analyst
Image Analyst il 9 Lug 2012
My guess would be that perhaps you didn't specify the folder in the list, and the files don't exist on the search path.

Categorie

Scopri di più su Data Import and Export in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by