How to get entropy values of different images to a graph?

1 visualizzazione (ultimi 30 giorni)
Hi,
I have calculated the entropy values of different images using the code I have shown below. Now I need to get the entropy values o several images to a graph. Can you please help me on that?
%read te image
I = imread('152.bmp');
subplot(2,2,1),imshow(I,map1)
I2 = imread('006.bmp');
subplot(2,2,3),imshow(I2,map2)
x = entropy(I);
x2 = entropy(I2);
[Height,Width] = size(I);
[m,Binsx] = imhist(I);
%normalize the counts
m = m/(Height*Width);
%get the sum of the histogram values
sprintf('the sum of the histogram value is = %g',sum(m));
subplot(2,2,2),plot(Binsx,m,'k')
xlabel('pixel value'),ylabel('relative count')
H = sum(-m.*log2(m));
sprintf('the entropy of the image is = %g',H)
%calculate height & width of the image
[Height,Width] = size(I2);
%get the histogram of the image in 256 bins
[n,Binsx] = imhist(I2);
%normalize the counts
n = n/(Height*Width);
%get the sum of the histogram values
sprintf('the sum of the histogram value is = %g',sum(n));
%
subplot(2,2,4),plot(Binsx,n,'k')
xlabel('pixel value'),ylabel('relative count')
H2 = sum(-n.*log2(n));
sprintf('the entropy of the image is = %g',H2)
%get the graph of the entropy values
figure(),plot(H,H2);
xlabel('image number'),ylabel('entropy value')
  1 Commento
Image Analyst
Image Analyst il 25 Nov 2018
Do you want both entropy values on one graph? Why not use bar() instead of plot()?

Accedi per commentare.

Risposta accettata

KALYAN ACHARJYA
KALYAN ACHARJYA il 25 Nov 2018
I=imread('test.png');
I2=imread('test.jpg');
x=entropy(I);
x2=entropy(I2);
bar([x x2]);
set(gca,'xticklabel');
title('Entropy of Two Images');
rrr.png
Another Way:
I=imread('test.png');
I2=imread('test.jpg');
x=entropy(I);
x2=entropy(I2);
bar(1,x);
hold on;
bar(2, x2,'r');
bar_name={'Image 1' 'Image 2'};
legend(bar_name,'location','northwest');
title('Entropy of Two Images');
yy.png
  2 Commenti
Ishara Nipuni
Ishara Nipuni il 25 Nov 2018
Thank you so much for the help. It will be very helpfull for me. :-) :-)
KALYAN ACHARJYA
KALYAN ACHARJYA il 25 Nov 2018
Welcome @Ishara
I'm glad, it helped.
Good Wishes
Regards,
Kalyan Acharjya

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by