how to form a indexed matrix?

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Shubham Mohan Tatpalliwar
Shubham Mohan Tatpalliwar il 26 Nov 2018
Commentato: Jan il 26 Nov 2018
Row matrix
A=[0 2 3; 3 2 1; 2 3 1]
Column
B= 2
Index matrix
C=[10 20 50; 60 80 90 ; 20 60 40]
Result expected
i would first select colum As 2
And look for the values of C
Depending on row number from A
D=[0 80 60; 60 80 20; 80 60 20]

Risposta accettata

Jan
Jan il 26 Nov 2018
The quetsion is not really clear. With some bold guessing:
A = [1 2 3; 3 2 1; 2 3 1];
B = 2;
C = [10 20 50; 60 80 90 ; 20 60 40];
CB = C(:, B);
D = CB(A)
  3 Commenti
Shubham Mohan Tatpalliwar
Shubham Mohan Tatpalliwar il 26 Nov 2018
Can u suggest me something for zero terms
Jan
Jan il 26 Nov 2018
D = zeros(size(A));
m = (A ~= 0);
D(m) = CB(A(m));

Accedi per commentare.

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