How to generate a a restricted binary number
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Dear friends
I would like to generate a random number include 24 bits 4 bits of 1 and 20 bits of 0. Can you help me?
Best Regards
Mohsen
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Jan
il 5 Dic 2018
Modificato: Jan
il 5 Dic 2018
What exactly is a "number include 24 bits"?
This sets 4 elements to 1 and 20 to 0:
v = zeros(1, 24);
v(randperm(24, 4)) = 1;
What is the wanted output?
result = bin2dec('0' + v)
% or
result = v * power(2, 0:23).'
Instead of creating the sum using the dot product, you can use the indices replied by randperm directly:
result = sum(2 .^ (randperm(24, 4) - 1));
I hope this was not a homework question. Otherwise it will be hard for you to submit your own solution now. But you participate in this forum for 6 years now, such that I assume that you are not in the learning phase anymore.
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Più risposte (1)
Mohsen
il 5 Dic 2018
Modificato: Mohsen
il 5 Dic 2018
2 Commenti
Jan
il 6 Dic 2018
Modificato: Jan
il 6 Dic 2018
I do not understand what "number dimension, max and min" means. Maximum and minimum of what? My answer includes a method to create random vectors already:
v = zeros(1, 24);
v(randperm(24, 4)) = 1;
Do you now want to create all these vectors? Then:
M = nchoosek(1:24, 4);
for k = 1:size(M, 1)
v = zeros(1, 24);
v(M(k, :)) = 1;
...
end
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