find char indices (row,column)

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Juan Rosado
Juan Rosado il 12 Lug 2012
Grettings,
I have this html text file which I convert into a character array (38x343 char) using 'char' and I am triying to find the indices of all the lines starting with '<B>' using the command 'find'
So far I have typed this code,
[row,col]=find(strncmpi('outchar', '<B>', 3)) % outchar = variable of char array
but I keep getting empty brackets:
row =
[]
col =
[]
One line of the text file looks like this:
<B><FONT SIZE=+1 COLOR="#483D8B">COASTAL WATERS FORECAST
And I want MATLAB to output
row [3 4 5 6 ...] col [1:3 ....] % 1:3 = columns from 1 to 3
What can I type?

Risposta accettata

Jan
Jan il 13 Lug 2012
Modificato: Walter Roberson il 13 Lug 2012
Variables are not enclosed in quotes:
[row,col] = find(strncmpi(outchar, '<B>', 3))
In opposite to this strncmpi('outchar', '<B>', 3) searches in the string 'outchar', which does not start with '<B>'.
I assume a cell string would be more convenient and efficient than a CHAR matrix.
STRNCMPI replies a logical vector: TRUE if the string matchs, FALSE otherwise. Therefore FIND will give you the wanted row indices, but not the columns "[1:3, ...]".
  2 Commenti
Juan Rosado
Juan Rosado il 13 Lug 2012
Jan, thank you for your answer.
The thing is I am converting the text to character array because I want to display a specified data following the '<B>' tag
For example,
<FONT SIZE=+1 COLOR="#800000">TONIGHT</FONT>'
'EAST WINDS 11 TO 16 KNOTS. SEAS 2 TO 4 FEET. SCATTERED'
'SHOWERS.
I want MATLAB to display,
winds: 'EAST WINDS 11 TO 16 KNOT'
waves: 'SEAS 2 TO 4 FEET'
% divide the sentence in phrases using structured variables
and for this I need to generate a character array because a string would output the whole sentence which I dont want.
What do you suggest me?
F.
F. il 13 Lug 2012
I think you should use a cell array like Jan Simon.
After you have the command regexp to give you the position of the first character of your string. With the length, you’ll have your columns.

Accedi per commentare.

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