Count number of repeated element before next different number in array?

Hi,

This is the problem:

I have an array of size 1xN, and this array is filled with 1 and 0. What I want is to count the number of repeated ones before a zero.

I will try to explain with an example.

A = [1,1,1,0,0,0,0,1,0,0,1,1,0,0,0,1,1,1,1];

What I want the code to do is to count how many times the ones are repeated before a zero. So, the answer is

OnesRepeated = [3, 1, 2, 4]

Can anyone help please? Thanks

Answer 1

[Stephen23]

>> D = diff([0,A==1,0]);
>> find(D<0)-find(D>0)
ans =
   3   1   2   4

[S. Perez]

Perfect! Thanks.

Answer 2

[Adam]

runs = diff( [0 find( diff( A ) ) numel( A )] )
if A(1) == 1
   OnesRepeated = runs( 1:2:end );
else
   OnesRepeated = runs( 2:2:end );
end

[Rik]

Alternatively, you could use RunLength or search the FEX for other implementations.