how to search about a matrix in a cell?

Hello,

Suppose that I have the cell matrix A which contains the following elements:

A={ 
[0;0] [0;1] 
[1;0] [0;0]
}

So I want to use a line of code that can count how many [0;0] are in each row ?

Regards,

Answer 1

[Guillaume]

it's always a good idea to give the result you expect for your example to avoid ambiguity.

A={ 
[0;0] [0;1] 
[1;0] [0;0]
}

sum(cellfun(@(x) isequal(x, [0;0]), A), 2)

results in

ans =
     1
     1

count of [0;0] in each row.

[Sarah A]

Great ! Thank you for your answer.

Answer 2

[madhan ravi]

Sarah's (OP) example:

A={ ...
[0;0] [0;1] 
[1;0] [0;0]
};
counts=nnz(~cellfun(@any,A))

Gives:

counts =

     2

Stephen's example:

A={[0;0] [0;1] [1;0] [0;0] [0;0]};
counts=nnz(~cellfun(@any,A))

Gives:

counts =

     3

[Stephan]

consider:

A={[0;0] [0;1] [1;0] [0;0] [0;0]}

isnt your code doing the opposite of what the op asked for? i would expect a result of 3 for this case.

[madhan ravi]

See edited answer.

[Sarah A]

thank you for your answer but this is not what I need. what if I want to count how many [0;1] there ?

Also noticed that in my question I wrote each two matrices in a row thats mean A is (2*2 matrix)

[madhan ravi]

check the edited answer

[Sarah A]

Yes this code work with me:

A={ ...

[0;0] [0;1] 

[1;0] [0;0]

};

counts=nnz(~cellfun(@any,A))

but what if I want to count how many [0;0] in each row? how many [0;1] in each row? how many [1;1] in each row?