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Bug fminbnd not working

3 visualizzazioni (ultimi 30 giorni)
Stephen Wilkerson
Stephen Wilkerson il 20 Gen 2019
Modificato: Torsten il 17 Lug 2022
fplot(@(x) x*(sin(x))^2*cos(x),[-2*pi 2*pi]);
[xMin1 fvalmin1] = fminbnd('-x*(sin(x))^2*cos(x)', -6, 6)
returns xMin1 = 1.0954
fvalmin1 = -0.3963
How is this possible, look at the plot?
  3 Commenti
Stephen Wilkerson
Stephen Wilkerson il 20 Gen 2019
Not where the minimum is! look at the plot
Stephen Wilkerson
Stephen Wilkerson il 20 Gen 2019
Solved, The function doesn't really do much, it give you the nearest point that's a minimum to it's starting point. In my case it woud be 0 as the starting point. Typical

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Walter Roberson
Walter Roberson il 20 Gen 2019
No bug. fminbnd is a local minimizer, not a global minimizer.
  3 Commenti
Torsten
Torsten il 17 Lug 2022
Modificato: Torsten il 17 Lug 2022
Since the changes in the x-values are in the order of 1e-6, you must choose a smaller value for TolX:
a=-200; b=-979.8997; c=7.1833e+05; d=24.4232;e=-6.6083;
x1=0; x2=4.1135e-06;
f=@(x)a-(a-b)*cos(c*(x-x1)) + d*e*sin(c*(x-x1))
f = function_handle with value:
@(x)a-(a-b)*cos(c*(x-x1))+d*e*sin(c*(x-x1))
fplot(f, [x1 x2])
options = optimset('TolX',1e-8);
[xmin, min]=fminbnd(f, x1, x2, options)
xmin = 2.8422e-07
min = -996.4246
Zhe Yu
Zhe Yu il 17 Lug 2022
Hi Torsten, thank you very much!

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