if function error, here i want MatLab to find the values of V5L that are between 1 and 4.5 and name it V, and use it in another upcoming equation

1 visualizzazione (ultimi 30 giorni)
clear,clc,clf
Q=3.3;
D5L=[12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254]
V5L=((4.*Q)./(pi.*D5L.^2));
if V5L > 1 & V5L < 4.5
V=V5L
end
Do=((4.*Q)./(pi.*V)).^(0.5)

Risposta accettata

Star Strider
Star Strider il 27 Gen 2019
Modificato: Star Strider il 27 Gen 2019
This works for me:
Q = 3.3;
D5L = [12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254];
V5L = ((4.*Q)./(pi.*D5L.^2));
V = V5L((V5L > 1) & (V5L < 4.5));
Do = sqrt((4.*Q)./(pi.*V))
producing:
Do =
1.0160 1.0668 1.1176 1.1684 1.2192 1.3208 1.4224 1.5240 1.6256 1.7272 1.8288 1.9304 2.0320
EDIT — (27 Jan 2019 at 15:09)
This runs for me without error (in R2018b):
Q=3.3;
%gamma=8.43 kN/m3 = 859.62076503 Kg/m3 (*1000/9.81)
rouh=859.62076503;
g=9.81;
Gamma=(rouh.*g);
Zs=0;
Ze=0;
L=1285000;
Ks=(0.000045);
Er=(1E-8);
viscosity=(3.83.*1E-3);
% material grade X70
strength= 482000000;
%API 5L
% % D5L=[12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254]
% % V5L=((4.*Q)./(pi.*D5L.^2));
% % if V=V5L(V5L > 1 & abs(V5L - 4.5<1e-5));
% % end
% % Do=((4.*Q)./(pi.*V)).^(0.5)
D5L = [12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254];
V5L = ((4.*Q)./(pi.*D5L.^2));
V = V5L((V5L > 1) & (V5L < 4.5));
Do = sqrt((4.*Q)./(pi.*V));
Re=(V.*Do./viscosity);
Fo=0.01;
for I=0:1:1E6;
Fn=(1./(-4.*log10((Ks./(3.71.*Do))+((1.26)./(Re.*sqrt(Fo)))))).^2;
E=abs((Fn-Fo)/Fn);
if E<=Er;
Fn=Fn(end);
display(E)
break
end
if E>Er;
Fo=Fn;
end
end
Hloss=((Fn.*L.*Q.^2)./(12.*Do.^5));
Hpump=Hloss+Ze-Zs;
%calculating Hloss every 128500M
LC=1:128500:1285000;
for i=1:1:length(LC);
Hpump=Hloss+Ze-Zs;
PRESSURE=rouh.*g.*Hpump.*1E-5;
numberofpumps=ceil(PRESSURE./90);
pressureperpump=(PRESSURE./numberofpumps);
HlossN=((Fn.*LC(i).*Q.^2)./(12.*sqrt(Do)));
TEL(i,:)=(Hpump-HlossN+Zs);
HGL(i,:)=(TEL(i,:)-((V.^2)./(2.*g)));
PE=Gamma.*(HGL-Ze);
T=((PE(i).*Do)./(2.*strength));
end
for ii=1:1:length(Do)
subplot(4,4,ii)
plot(LC,TEL(:,ii))
hold on
plot(LC,HGL(:,ii))
xlabel('LC')
ylabel('HGL & TEL')
end

Più risposte (1)

madhan ravi
madhan ravi il 27 Gen 2019
Modificato: madhan ravi il 27 Gen 2019
EDITED
clear all
Q=3.3;
D5L=[12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254]
V5L=((4.*Q)./(pi.*D5L.^2));
V=V5L(V5L > 1 & V5L < 4.5);
Do=((4.*Q)./(pi.*V)).^(0.5);
  4 Commenti
omar mahallawy
omar mahallawy il 27 Gen 2019
clear,clc,clf
format short
Q=3.3;
%gamma=8.43 kN/m3 = 859.62076503 Kg/m3 (*1000/9.81)
rouh=859.62076503;
g=9.81;
Gamma=(rouh.*g);
Zs=0;
Ze=0;
L=1285000;
Ks=(0.000045);
Er=(1.*10.^-8);
viscosity=(3.83.*10.^-3);
% material grade X70
strength= 482000000;
%API 5L
D5L=[12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254]
V5L=((4.*Q)./(pi.*D5L.^2));
if V=V5L(V5L > 1 & abs(V5L - 4.5<1e-5));
end
Do=((4.*Q)./(pi.*V)).^(0.5)
Re=(V.*Do./viscosity)
Fo=0.01;
for I=0:1:10^6;
Fn=(1./(-4.*log10((Ks./(3.71.*Do))+((1.26)./(Re.*sqrt(Fo)))))).^2;
E=abs((Fn-Fo)/Fn);
if E<=Er;
Fn=Fn(end),display(E),break,
end
if E>Er;
Fo=Fn;
end
end
Hloss=((Fn.*L.*Q.^2)./(12.*Do.^5))
Hpump=Hloss+Ze-Zs
%calculating Hloss every 128500M
LC=1:128500:1285000;
for i=1:1:length(LC);
Hpump=Hloss+Ze-Zs
PRESSURE=rouh.*g.*Hpump.*10.^(-5)
numberofpumps=ceil(PRESSURE./90)
pressureperpump=(PRESSURE./numberofpumps)
HlossN=((Fn.*LC(i).*Q.^2)./(12.*Do.^5))
TEL(i,:)=(Hpump-HlossN+Zs)
HGL(i,:)=(TEL(i,:)-((V.^2)./(2.*g)))
PE=Gamma.*(HGL-Ze)
T=((PE(i).*Do)./(2.*strength))
end
for ii=1:1:length(Do)
subplot(4,4,ii)
plot(LC,TEL(:,ii))
hold on
plot(LC,HGL(:,ii))
xlabel('LC')
ylabel('HGL & TEL')
end
madhan ravi
madhan ravi il 27 Gen 2019
clear,clc,clf
format short
Q=3.3;
%gamma=8.43 kN/m3 = 859.62076503 Kg/m3 (*1000/9.81)
rouh=859.62076503;
g=9.81;
Gamma=(rouh.*g);
Zs=0;
Ze=0;
L=1285000;
Ks=(0.000045);
Er=(1.*10.^-8);
viscosity=(3.83.*10.^-3);
% material grade X70
strength= 482000000;
%API 5L
D5L=[12.75*0.0254 14*0.0254 16*0.0254 18*0.0254 20*0.0254 22*0.0254 24*0.0254 26*0.0254 28*0.0254 30*0.0254 32*0.0254 34*0.0254 36*0.0254 38*0.0254 40*0.0254 42*0.0254 44*0.0254 46*0.0254 48*0.0254 52*0.0254 56*0.0254 60*0.0254 64*0.0254 68*0.0254 72*0.0254 76*0.0254 80*0.0254]
V5L=((4.*Q)./(pi.*D5L.^2));
V=V5L(V5L > 1 & abs(V5L - 4.5<1e-5));
Do=((4.*Q)./(pi.*V)).^(0.5)
Re=(V.*Do./viscosity)
Fo=0.01;
for I=0:10^6
Fn=(1./(-4.*log10((Ks./(3.71.*Do))+((1.26)./(Re.*sqrt(Fo)))))).^2;
E=abs((Fn-Fo)/Fn);
if E<=Er
Fn=Fn(end);
display(E)
break
else
Fo=Fn;
end
end
Hloss=((Fn.*L.*Q.^2)./(12.*Do.^5));
Hpump=Hloss+Ze-Zs;
%calculating Hloss every 128500M
LC=1:128500:1285000;
TEL=zeros(numel(LC),numel(Do));
HGL=zeros(numel(LC),numel(Do));
PE=zeros(numel(LC),numel(Do));
T=zeros(numel(LC),numel(Do));
for k=1:numel(LC)
HlossN=((Fn.*LC(k).*Q.^2)./(12.*Do.^5));
TEL(k,:)=(Hpump-HlossN+Zs);
HGL(k,:)=(TEL(k,:)-((V.^2)./(2.*g)));
PE(k,:)=Gamma.*(HGL(k,:)-Ze);
T(k,:)=((PE(k,:).*Do)./(2.*strength));
end
for ii=1:numel(Do)
subplot(4,4,ii)
plot(LC,TEL(:,ii))
hold on
plot(LC,HGL(:,ii))
xlabel('LC')
ylabel('HGL & TEL')
end

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