convert number to string problem

I have a column number, and I want to add some string in front of it, and assign it to items of a drop-down list in an App.
take the test value test=1:1:5 for example, below is my code:
test=1:1:5;
for i=1:1:length(test)
tmp_name{i}=strcat('Data Set',num2str(test(i)));
end
to improve this code without the for-loop, I found that there is a function 'num2cell' but it does not work in this case:
test=1:1:5;
strcat('CVG Set',num2cell(test))
below is the result:
Capture.JPG
the numbers are converted to a rectangle symbol instead of string.
is there any mistake with my operation?
Bests,
Yu

 Risposta accettata

sprintfc('Data Set %d',test) % beware undocumented

2 Commenti

Alternative:
cellstr("Data set "+test)
Yu Li
Yu Li il 10 Mar 2019
Thank you.
Bests,
Yu

Accedi per commentare.

Più risposte (2)

Yu - I think the problem might be because when you use num2cell, you are creating a cell array of numbers and not a cell array of strings.
An alternative to what you have written is to use arrayfun where we apply a function to each of our integers (in test). For example,
tmp_name = arrayfun(@(x)sprintf('CVG Set %d',x),1:5, 'UniformOutput', false);
initializes the variable to
tmp_name =
'CVG Set 1' 'CVG Set 2' 'CVG Set 3' 'CVG Set 4' 'CVG Set 5'
which may be sufficient for what you need. You can modify the string in the sprintf call to get a different format (if that is what you need).
Yu:
Try this:
test = 1 : 5;
for k = 1 : length(test)
popupStrings{k} = sprintf('Data Set %d', test(k));
end
celldisp(popupStrings)
% Now load the strings into the popup (drop down list)
handles.popup1.String = popupStrings;

2 Commenti

OP tries to avoid a for-loop.
Yu Li
Yu Li il 10 Mar 2019
Thank you.
Bests,
Yu

Accedi per commentare.

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Richiesto:

il 10 Mar 2019

Commentato:

il 10 Mar 2019

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