Removing zeros from start of an array and inserting them at the end of same array

Let say I have an array

A = [ 0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0 ]

I would like to know wheter is there any way to move starting four zeros to the end of same array A.

The result should be

Result = [ 1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 ]

Now, in this example there were only four zeros. I do have arrays which have more than 4 zeros.

Thanks

Answer 1

[Alex Mcaulley]

Try this:

A = [0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0];
idx = find(A>0,1);
B = [A(idx:end),zeros(1,idx-1)]

[Shahab Khan]

Thank you. Works like a charm.

[Alex Mcaulley]

A = [0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0];
idx = find(A>0,1);
B = [A(idx:end),zeros(1,idx-1)];
B(~B) = max(B);

[Shahab Khan]

Thank you, actually i figured that out myself so i deleted the question. But anyway Thanks alot.

Answer 2

[Matt J]

n=find(A,1);
Result=circshift(A,1-n);

[Shahab Khan]

Thank you

Answer 3

[Sheng Chen]

Try this

A = [ 0,1,0,3,12];
idx = 1;
for j = 1 : numel(A)
    if A(j) ~= 0
        % swap A(j) and A(idx)
        A([j idx]) = A([idx j]);
        idx = idx + 1;
    end
end

[Shahab Khan]

Thank you