p = [2 3 4 5 6 7 8 9 10];
L2 = zeros(size(p));
xchange = zeros(size(p));
f = @(x) (cos(2*x)).*(sin(x)-0.5*x.^2);
for j = 1:length(p)
n = 2^(p(j));
x = linspace(-3,3,n);
dx = x(2)-x(1);
L = 0;
ff = [];
for i = 3:(length(x)-2)
ff = (-f(x(i+2))+6*f(x(i+1))-3*f(x(i))-2*f(x(i-1)))/(6*dx);
%ff = (-1*x(i+2)+6*x(i+1)-3*x(i)-2*x(i-1))/(6*dx);
L(i) = dx*((f(x(i))-ff)^2);
L = L + L(i);
end
%ff(1:2) = ff(3);
%ff(n-1:n) = ff(n-2);
L2(j) = L.^0.5;
xchange(j) = dx;
end
plot(log(xchange),log(L2))
hold on
Hi, can anyone help me with this. I have been spending hours to solve the error printed in the command window below;
"Unable to perform assignment because the left and right sides have a different number of
elements.
Error in Untitled2 (line 24)
L2(j) = L.^0.5;"

2 Commenti

Mohammad - in the line of code
L2(j) = L.^0.5;
L2 is a 9x9 matrix and L is an array of different lengths (depending upon p). So the above code is trying to assign an array to a scalar element of your L2 matrix. Do you really mean to assign an array here? Should L2 be a cell array so that you can assign differently sized vectors/arrays to it?
Thank you for your reply,
i have changed the two lines below....
L2 = zeros(1,length(p));
xchange = zeros(1,length(p));
... and yet still getting the same error message.

Accedi per commentare.

 Risposta accettata

Matt J
Matt J il 18 Mar 2019
Modificato: Matt J il 18 Mar 2019
for i = 3:(length(x)-2)
ff(i) = (-1*x(i+2)+6*x(i+1)-3*x(i)-2*x(i-1))/(6*dx);
L = L + dx*((f(x(i))-ff(i))^2);
end

4 Commenti

x(i+2) , x(i+1), x(i) and x(i-1) terms should be substituted in f from the 4th line.
Matt J
Matt J il 18 Mar 2019
Please Accept-click the answer if you are not getting the error anymore.
still getting error message
It runs fine for me.
p = [2 3 4 5 6 7 8 9 10];
L2 = zeros(size(p));
xchange = zeros(size(p));
f = @(x) (cos(2*x)).*(sin(x)-0.5*x.^2);
for j = 1:length(p)
n = 2^(p(j));
x = linspace(-3,3,n);
dx = x(2)-x(1);
L = 0;
ff = [];
for i = 3:(length(x)-2)
ff = (-f(x(i+2))+6*f(x(i+1))-3*f(x(i))-2*f(x(i-1)))/(6*dx);
%ff = (-1*x(i+2)+6*x(i+1)-3*x(i)-2*x(i-1))/(6*dx);
L = L + dx*((f(x(i))-ff)^2);
end
%ff(1:2) = ff(3);
%ff(n-1:n) = ff(n-2);
L2(j) = L.^0.5;
xchange(j) = dx;
end
plot(log(xchange),log(L2))
untitled.png

Accedi per commentare.

Più risposte (0)

Categorie

Prodotti

Release

R2018a

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by