residual r=ax-b ∞-norm

This is my code but i dont get the coorect answer
a = [-5 8 -5; 0 0 12; 3 -7 -3;6 -4 4]
b = [1;1;1;1]
x=a\b
r=a*x-b
x1=sqrt(sum(r.*r))

 Risposta accettata

dulanga
dulanga il 19 Mar 2019

0 voti

Would this be correct to get infinty norm
a = [-5 8 -5; 0 0 12; 3 -7 -3;6 -4 4]
b = [1;1;1;1]
x=a\b
r=a*x-b
N = norm(r, Inf)

4 Commenti

Torsten
Torsten il 19 Mar 2019
Apart from the rounding of the residual required for your homework, it's ok.
dulanga
dulanga il 19 Mar 2019
thanks
John D'Errico
John D'Errico il 19 Mar 2019
That is correct, as long as you are allowed to use the norm function. Things like that are sometimes not allowed in homework. If not, then you need to do as I suggested, as
max(abs( r ))
dulanga
dulanga il 19 Mar 2019
noted

Accedi per commentare.

Più risposte (1)

John D'Errico
John D'Errico il 19 Mar 2019
Why would you possibly have expected to get the right answer? Was the infinity norm requested? Is it a 2-norm that you computed?
x1=sqrt(sum(r.*r))
If r is the vector of residuals, then what do you want to compute? It seems like you want the maximum of the absolute value of the residuals. How would you do that?

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Richiesto:

il 18 Mar 2019

Commentato:

il 19 Mar 2019

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