using 'fsolve'
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I have the function f(x,y) = x.^(2-x.^(0.5))+y.^(2-y.^(0.5)) and I found the Jacobian and Hessian Matrices. Now I need to find the turning point using the function "fsolve" and stating its nature.
Can anyone help me?
Thanks in advance.
1 Commento
Walter Roberson
il 21 Mar 2019
The "turning points" are all the points where the derivative are 0.
You already have the derivative when you formed the Jocobian.
Risposta accettata
Stephan
il 21 Mar 2019
Hi,
why not solve it symbolic:
syms f(x,y)
f(x,y) = x.^(2-x.^(0.5))+y.^(2-y.^(0.5));
[xsol,ysol] = vpasolve(diff(f,x) + diff(f,y) == 0, [x,y], [1 3; 1 3]);
zsol = subs(f,[x,y],[xsol,ysol]);
% plot results
fsurf(f)
hold on
scatter3(double(xsol),double(ysol),double(zsol),'or','LineWidth',2,'MarkerFaceColor','r')
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