RK2 and modified euler's method

3 visualizzazioni (ultimi 30 giorni)
Ammar Alsenani
Ammar Alsenani il 4 Apr 2019
a=1;
b=2;
w0=1;
h=[0.5 0.1 0.05 0.01 0.005 0.001];
f=@(t,w) (w/t)-(w/t)^2;
wnA=zeros(1,6);
RE_mod=zeros(1,6);
wnB=zeros(1,6);
RE_mid=zeros(1,6);
for i=1:6
w=w0;
t=a;
for j=1:(b-a)/h(i)
w=w+h(i)*f(t,w);
t=a+j*h(i);
end
wnA(i)=w;
RE_mod(i)=abs(t/(log(t)+1));
end
for i=1:6
w=w0;
t=a;
tic
for j=1:(b-a)/h(i)
w=w+h(i)*f(t+h/2,w+h/2*f(t,w));
t=a+j*h(i);
time=toc;
end
wnB(i)=w;
RE_mid(i)=abs(t*log(t)+2*t);
end
loglog(h,RE_mid,'-+',h,RE_mod,'-o')
legend('Midpoint=RK2','Modified Euler')
xlabel('h')
ylabel('Relative Error')
%%this is my code but somthing is wrong with it, the graphs are strirtght horizental lines.

Risposte (0)

Categorie

Scopri di più su Graph and Network Algorithms in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by