Set() hPlot question

Hello, I have a 3 X 63950 double worth of data, and have been trying to plot it using set(hPlot1,'Xdata',...,'Ydata',...); but cant figure out what the problem is.

NOTE: Data is a (3 X127900) double I want to plot a certain number of values.

  set(hPlot1, 'Xdata',1:63950,'Ydata',Data(:,1:2:end));

[Walter Roberson]

Is hPlot1 a scalar handle or a vector of handles?

[m j]

Vector, but its been a long time since I used matlab so, forgive me if its something very simple. But I setup my plots,sublots like so....

hAxes1 = subplot(2,3,1);

hPlot1 = plot(hAxes1,NaN,NaN);

Answer 1

[Walter Roberson]

You need to use the obscure syntax for set in which the first parameter is a vector of handles and the second input is a cell array of character vectors indicating the properties to change and the third parameter is a cell array of new values carefully arranged.

When you call set with a vector of handles and the next parameter is a character vector, then that is a request to set that property to the same value for all of the handles. set does *not* have a syntax like

set([h1, h2], 'YData', {h1ydata, h2ydata})  %invalid
set([h1, h2], 'YData', [h1ydata(:), h2ydata(:)])  %would set both handles to same value

The only syntax for set() that permits different values for different handles on the same call is the cell array of character vectors one that is a bit confusing to set up.

Most of the time it is easier and clearer to just use a loop or arrayfun or cellfun. I only use the cell array of character vectors properties syntax if efficiency is especially important... Or sometimes with a scalar handle if I used get with a cell array of character vectors to query multiple properties.