How do I sample a random value from a normal distribution

I want to sample a value from a normal distribution and I wrote down this codes. Can someone please look at it and hint me if it is appropriate. I am Matlab basic user.

r=rand;
ci_l=find(cumu<=r,1,'last');
ci_h=find(cumu>=r,1,'first');
if abs(cumu(ci_l)-r)<=abs(cumu(ci_h)-r)
    ci=ci_l;
else
    ci=ci_h;
end

cmuO=getCDF(pdfY);
cmuO=cmuO/max(cmuO);

[~,idx]=min(abs(cmuO-cumu(ci)));
newVal=pdfX(idx);

[Walter Roberson]

??

normrnd() perhaps ?

[Gumps]

Hi Walter,

What I meant is sampling just one random value from a normal distribution. I have typed the codes I generated. Do you think its sufficient?

[Walter Roberson]

I do not understand the point of any of that.

Is cumu a previously initialized vector of randn() values? Sorted output of randn() in particular?

I do not understand what you think you are calculating.

[Gumps]

Cumu is an existing distribution.

i therefore want to sample a random value from it.

[Walter Roberson]

Is Cumu a distribution created with makedist() https://www.mathworks.com/help/stats/makedist.html or is it a vector of values ? If it is a vector, is the vector sorted in increasing order?

[Gumps]

Cumu was created somewhat with code related with makedist().

YES

[Walter Roberson]

Is the "YES" intended to mean that Yes, it is a vector sorted in increasing order?

Answer 1

[James Tursa]

doc randn