Nested Loop Script (Triangle)

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Write a nested llop script that will print the following pattern, printing one number or character at a time starting at 1 and using the numbers 0 through 9Screen Shot 2019-04-28 at 1.24.24 PM.png
  3 Commenti
Juan Zegarra
Juan Zegarra il 28 Apr 2019
This but im not sure what to print or how to do it for the first one.
for n=1:5
for s=1:n
fprintf('')
end
fprintf('\n')
end
Cedric
Cedric il 28 Apr 2019
Modificato: Cedric il 28 Apr 2019
It is a good start, you can try to display a charater followed by a space, just to make sure that your nested loops operate as desired:
for n = 1 : 5
for m = 1 : n
fprintf('A ') ;
end
fprintf('\n') ;
end
which outputs:
A
A A
A A A
A A A A
A A A A A
It looks like it is working. Now you solved one part of the problem, and there are many ways to solve the rest.
What happens if you keep incrementing some variable within the inner loop?
s = 1 ;
for n = 1 : 5
for m = 1 : n
fprintf('A ') ; % What about displaying the value of s instead of 'A '?
s = s + 1 ;
end
fprintf('\n') ;
end
Are you able to print the value of s instead of this character A? Maybe then you'll want to read about the modulo operation.

Accedi per commentare.

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Sulaymon Eshkabilov
Sulaymon Eshkabilov il 6 Mag 2019
Modificato: Sulaymon Eshkabilov il 6 Mag 2019
Here is the complete answer to all parts of the assignment:
%%
clearvars; clc
%% Part 1.
k=1;
for ii = 1 : 5
for jj = 1 : ii
if k >10
k=k-10;
fprintf(num2str(k));
else
fprintf(num2str(k)) ;
end
k = k+1;
end
fprintf('\n') ;
end
%% Part 2
k = 65 ;
for ii = 1 : 5
for jj = 1 : ii
fprintf(char(k)) ;
k = k + 1 ;
end
fprintf('\n') ;
end
%% Part 3. Numbers
k=5;
for ii = 1 : 5
for jj = 1 : ii
if k >10
k=k-10;
fprintf(num2str(k));
else
fprintf(num2str(k)) ;
end
k = k+1;
end
fprintf('\n') ;
end
%% Part 3. Letters
k = 68 ;
for ii = 1 : 5
for jj = 1 : ii
fprintf(char(k) ) ;
k = k + 1 ;
end
fprintf('\n') ;
end

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