NaN with backslash operator
12 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hi,
I would like to understand the reason as to why the below operation is giving a NaN solution for the attached data.
x = A\B;
Thank you.
YK..
0 Commenti
Risposta accettata
Adam Danz
il 29 Apr 2019
The following rows of your variable "B" contain NaN values.
find(isnan(B))
ans =
1491
1492
1493
1494
1495
1496
1497
To ignore the NaN values,
nanIdx = isnan(A) | isnan(B);
A(~nanIdx) \ B(~nanIdx)
ans =
-0.091457
2 Commenti
John D'Errico
il 29 Apr 2019
The problem being that NaNs propagate. Everything they touch, turns to NaN. (Like old King MIdas, but in an even worse way.) So if you already have NaNs in your data, give it up. You need to excise them from your data before any linear algebra computations.
Steven Lord
il 29 Apr 2019
FYI the functions listed in the "Missing Data and Outliers" section of this documentation page may be of use in locating, removing, and/or replacing the NaN values in the data.
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Logical in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!